[ragel-users] Strange difference between C and Java

[Adrian Thurston]

Hi Jose,

It looks like there is no newline on the end of the string being passed 
to the Java version. That could be it.

-Adrian

Jose Quinteiro wrote:
> I have created what I think are identical machines (except for the host 
> code, that is) that don't behave the same way.  The ragel files are 
> attached.
> 
> Here's a typical session with the C machine:
> 
> $ ragel client_c.rl
> $ gcc -o client_c client_c.c
> $ echo "OK callnum 8108" | ./client_c
> figure out how to print out the call number.
> $ echo "OK callnum 8108 foo" | ./client_c
> Parse error.
> 
> 
> Here's the same session with the Java machine:
> 
> $ ragel -J client_java.rl -o ClientParser.java
> $ javac ClientParser.java
> $ java ClientParser "OK callnum 8108"
> $ java ClientParser "OK callnum 8108 foo"
> Parse error.
> 
> 
> It seems like the "%" transition action works differently in Java and C. 
>  If I change the transition action to and "@" I get "figure out how to 
> print out the call number." several times. This is true for both the C 
> and Java versions.
> 
> What am I doing wrong?
> 
> Thanks,
> Jose.
> 
> 
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