[ragel-users] Strange difference between C and Java

[Jose Quinteiro]

I figured I missing something simple.  Thanks for the quick reply!

Adrian Thurston wrote:
> Hi Jose,
> 
> It looks like there is no newline on the end of the string being passed 
> to the Java version. That could be it.
> 
> -Adrian
> 
> Jose Quinteiro wrote:
>> I have created what I think are identical machines (except for the host 
>> code, that is) that don't behave the same way.  The ragel files are 
>> attached.
>>
>> Here's a typical session with the C machine:
>>
>> $ ragel client_c.rl
>> $ gcc -o client_c client_c.c
>> $ echo "OK callnum 8108" | ./client_c
>> figure out how to print out the call number.
>> $ echo "OK callnum 8108 foo" | ./client_c
>> Parse error.
>>
>>
>> Here's the same session with the Java machine:
>>
>> $ ragel -J client_java.rl -o ClientParser.java
>> $ javac ClientParser.java
>> $ java ClientParser "OK callnum 8108"
>> $ java ClientParser "OK callnum 8108 foo"
>> Parse error.
>>
>>
>> It seems like the "%" transition action works differently in Java and C. 
>>  If I change the transition action to and "@" I get "figure out how to 
>> print out the call number." several times. This is true for both the C 
>> and Java versions.
>>
>> What am I doing wrong?
>>
>> Thanks,
>> Jose.
>>
>>
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>>
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