[ragel-users] Parser help

[Adrian Thurston]

Hi,

The only way to do this is to either take a pointer to everything up to, 
but not including the newline, then chomp off the trailing '==='. This 
is because the state machine is capable of the representing the notion 
of being in more than one state at once, but the data collection 
mechanism is not. You can ask the pioneers of computer science why that 
is ;)

-Adrian

On 11-01-27 11:38 PM, S.Geist wrote:
> I'm trying to build a parser for text lines of the form:
>
> === line: {any chars here except \n} ===\n
>
> I don't think I comprehend too well the way Ragel works, because I'm
> failing miserably at my task.
> Here's the code I've came up with: http://pastebin.com/rtp3dRSV
>
> And the output:
>
>
> $ echo "=== line: balpblap lapsl = klbokqe pblpel ===" | ./a.out
> balpblap lapsl
> balpblap lapsl = klbokqe pblpel
> balpblap lapsl = klbokqe pblpel =
> balpblap lapsl = klbokqe pblpel ==
>
> What I need to do is extract the "{any chars here except \n}" part;
> can anyone give me some hints on how to achieve this?
>
> Thanks in advance!
>
> _______________________________________________
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> ragel-users at complang.org
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>

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